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340412443303 = 2704312587821
BaseRepresentation
bin1001111010000100010…
…10011010101010100111
31012112122221001212002111
410331002022122222213
521034131041141203
6420214444021451
733410511011632
oct4750212325247
91175587055074
10340412443303
11121405a4a079
1255b83531887
132614048b45a
14126943d2c19
158cc54b626d
hex4f4229aaa7

340412443303 has 4 divisors (see below), whose sum is σ = 340425058168. Its totient is φ = 340399828440.

The previous prime is 340412443289. The next prime is 340412443339. The reversal of 340412443303 is 303344214043.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 340412443303 - 233 = 331822508711 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (340412443003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6266868 + ... + 6320953.

It is an arithmetic number, because the mean of its divisors is an integer number (85106264542).

Almost surely, 2340412443303 is an apocalyptic number.

340412443303 is a deficient number, since it is larger than the sum of its proper divisors (12614865).

340412443303 is a wasteful number, since it uses less digits than its factorization.

340412443303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12614864.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 340412443303 its reverse (303344214043), we get a palindrome (643756657346).

The spelling of 340412443303 in words is "three hundred forty billion, four hundred twelve million, four hundred forty-three thousand, three hundred three".

Divisors: 1 27043 12587821 340412443303