340413301225333 has 4 divisors (see below), whose sum is σ = 389043772828960. Its totient is φ = 291782829621708.

The previous prime is 340413301225321. The next prime is 340413301225337. The reversal of 340413301225333 is 333522103314043.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 340413301225333 - 2³⁷ = 340275862271861 is a prime.

It is a super-2 number, since 2×340413301225333² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 340413301225292 and 340413301225301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (340413301225337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24315235801803 + ... + 24315235801816.

It is an arithmetic number, because the mean of its divisors is an integer number (97260943207240).

Almost surely, 2^{340413301225333} is an apocalyptic number.

It is an amenable number.

340413301225333 is a deficient number, since it is larger than the sum of its proper divisors (48630471603627).

340413301225333 is an equidigital number, since it uses as much as digits as its factorization.

340413301225333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48630471603626.

The product of its (nonzero) digits is 233280, while the sum is 37.

Adding to 340413301225333 its reverse (333522103314043), we get a palindrome (673935404539376).

The spelling of 340413301225333 in words is "three hundred forty trillion, four hundred thirteen billion, three hundred one million, two hundred twenty-five thousand, three hundred thirty-three".