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34043101513 = 71479480303
BaseRepresentation
bin11111101101001000…
…001000000101001001
310020212112002201222121
4133231020020011021
51024210013222023
623350021451241
72313422405551
oct375510100511
9106775081877
1034043101513
111348a497043
126720b70b21
133296bc7c65
14190d3bc161
15d43a64d5d
hex7ed208149

34043101513 has 4 divisors (see below), whose sum is σ = 34522581888. Its totient is φ = 33563621140.

The previous prime is 34043101501. The next prime is 34043101549. The reversal of 34043101513 is 31510134043.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34043101513 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (34043101913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 239740081 + ... + 239740222.

It is an arithmetic number, because the mean of its divisors is an integer number (8630645472).

Almost surely, 234043101513 is an apocalyptic number.

It is an amenable number.

34043101513 is a deficient number, since it is larger than the sum of its proper divisors (479480375).

34043101513 is an equidigital number, since it uses as much as digits as its factorization.

34043101513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 479480374.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 34043101513 its reverse (31510134043), we get a palindrome (65553235556).

The spelling of 34043101513 in words is "thirty-four billion, forty-three million, one hundred one thousand, five hundred thirteen".

Divisors: 1 71 479480303 34043101513