Base | Representation |
---|---|
bin | 11111101101001001… |
… | …010100011001100001 |
3 | 10020212112200121210101 |
4 | 133231021110121201 |
5 | 1024210103222423 |
6 | 23350032302401 |
7 | 2313425150122 |
oct | 375511243141 |
9 | 106775617711 |
10 | 34043414113 |
11 | 1348a68a995 |
12 | 67210a1a01 |
13 | 3296ca7327 |
14 | 190d460049 |
15 | d43ac77ad |
hex | 7ed254661 |
34043414113 has 4 divisors (see below), whose sum is σ = 34192075540. Its totient is φ = 33894752688.
The previous prime is 34043414089. The next prime is 34043414117. The reversal of 34043414113 is 31141434043.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 18650545489 + 15392868624 = 136567^2 + 124068^2 .
It is a cyclic number.
It is not a de Polignac number, because 34043414113 - 25 = 34043414081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34043414117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74330370 + ... + 74330827.
It is an arithmetic number, because the mean of its divisors is an integer number (8548018885).
Almost surely, 234043414113 is an apocalyptic number.
It is an amenable number.
34043414113 is a deficient number, since it is larger than the sum of its proper divisors (148661427).
34043414113 is a wasteful number, since it uses less digits than its factorization.
34043414113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 148661426.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 34043414113 its reverse (31141434043), we get a palindrome (65184848156).
The spelling of 34043414113 in words is "thirty-four billion, forty-three million, four hundred fourteen thousand, one hundred thirteen".
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