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34044114113 = 41278249119
BaseRepresentation
bin11111101101001011…
…111111010011000001
310020212121000012000022
4133231023333103001
51024210243122423
623350055303225
72313434124002
oct375513772301
9106777005008
1034044114113
11134900188a9
12672137ab15
133297190b29
14190d5a31a9
15d43bb4dc8
hex7ed2ff4c1

34044114113 has 4 divisors (see below), whose sum is σ = 34052367360. Its totient is φ = 34035860868.

The previous prime is 34044114107. The next prime is 34044114227. The reversal of 34044114113 is 31141144043.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 34044114113 - 212 = 34044110017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (34044119113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4120433 + ... + 4128686.

It is an arithmetic number, because the mean of its divisors is an integer number (8513091840).

Almost surely, 234044114113 is an apocalyptic number.

It is an amenable number.

34044114113 is a deficient number, since it is larger than the sum of its proper divisors (8253247).

34044114113 is an equidigital number, since it uses as much as digits as its factorization.

34044114113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8253246.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 34044114113 its reverse (31141144043), we get a palindrome (65185258156).

The spelling of 34044114113 in words is "thirty-four billion, forty-four million, one hundred fourteen thousand, one hundred thirteen".

Divisors: 1 4127 8249119 34044114113