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34044150433 = 53642342461
BaseRepresentation
bin11111101101001100…
…001000001010100001
310020212121002000211111
4133231030020022201
51024210300303213
623350100143321
72313434334616
oct375514101241
9106777060744
1034044150433
1113490043117
126721397b41
1332971a4517
14190d5b250d
15d43bc0a3d
hex7ed3082a1

34044150433 has 4 divisors (see below), whose sum is σ = 34686492948. Its totient is φ = 33401807920.

The previous prime is 34044150383. The next prime is 34044150443. The reversal of 34044150433 is 33405144043.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8436789904 + 25607360529 = 91852^2 + 160023^2 .

It is a cyclic number.

It is not a de Polignac number, because 34044150433 - 225 = 34010596001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34044150395 and 34044150404.

It is not an unprimeable number, because it can be changed into a prime (34044150443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321171178 + ... + 321171283.

It is an arithmetic number, because the mean of its divisors is an integer number (8671623237).

Almost surely, 234044150433 is an apocalyptic number.

It is an amenable number.

34044150433 is a deficient number, since it is larger than the sum of its proper divisors (642342515).

34044150433 is an equidigital number, since it uses as much as digits as its factorization.

34044150433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 642342514.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 34044150433 its reverse (33405144043), we get a palindrome (67449294476).

The spelling of 34044150433 in words is "thirty-four billion, forty-four million, one hundred fifty thousand, four hundred thirty-three".

Divisors: 1 53 642342461 34044150433