Base | Representation |
---|---|
bin | 1111011111001001010110… |
… | …10000000100000010011001 |
3 | 11110120200020211112210201200 |
4 | 13233210223100010002121 |
5 | 13430431201424233423 |
6 | 200232520203504413 |
7 | 10113300365010225 |
oct | 757445320040231 |
9 | 143520224483650 |
10 | 34055521321113 |
11 | a93a957a61a76 |
12 | 39a0231228109 |
13 | 1600563b44bc6 |
14 | 85a420423785 |
15 | 3e0ce020ad43 |
hex | 1ef92b404099 |
34055521321113 has 12 divisors (see below), whose sum is σ = 49192994800560. Its totient is φ = 22702902622776.
The previous prime is 34055521321111. The next prime is 34055521321141. The reversal of 34055521321113 is 31112312555043.
It is a happy number.
34055521321113 is a `hidden beast` number, since 3 + 40 + 55 + 521 + 32 + 1 + 1 + 13 = 666.
It is not a de Polignac number, because 34055521321113 - 21 = 34055521321111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (34055521321111) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 64577631 + ... + 65102852.
It is an arithmetic number, because the mean of its divisors is an integer number (4099416233380).
Almost surely, 234055521321113 is an apocalyptic number.
It is an amenable number.
34055521321113 is a deficient number, since it is larger than the sum of its proper divisors (15137473479447).
34055521321113 is a wasteful number, since it uses less digits than its factorization.
34055521321113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 129709668 (or 129709665 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 36.
Adding to 34055521321113 its reverse (31112312555043), we get a palindrome (65167833876156).
The spelling of 34055521321113 in words is "thirty-four trillion, fifty-five billion, five hundred twenty-one million, three hundred twenty-one thousand, one hundred thirteen".
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