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341002103 = 1326230931
BaseRepresentation
bin10100010100110…
…100011101110111
3212202122200221112
4110110310131313
51144244031403
653500505235
711310320141
oct2424643567
9782580845
10341002103
11165539a22
129624b21b
13558557c0
1433407c91
151ee0c9d8
hex14534777

341002103 has 4 divisors (see below), whose sum is σ = 367233048. Its totient is φ = 314771160.

The previous prime is 341002091. The next prime is 341002121. The reversal of 341002103 is 301200143.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301200143 = 1901158443.

It is a cyclic number.

It is not a de Polignac number, because 341002103 - 222 = 336807799 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (341002003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13115453 + ... + 13115478.

It is an arithmetic number, because the mean of its divisors is an integer number (91808262).

Almost surely, 2341002103 is an apocalyptic number.

341002103 is a deficient number, since it is larger than the sum of its proper divisors (26230945).

341002103 is a wasteful number, since it uses less digits than its factorization.

341002103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26230944.

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 341002103 is about 18466.2422544491. The cubic root of 341002103 is about 698.6382389794.

Adding to 341002103 its reverse (301200143), we get a palindrome (642202246).

The spelling of 341002103 in words is "three hundred forty-one million, two thousand, one hundred three".

Divisors: 1 13 26230931 341002103