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34102140053 = 64752708099
BaseRepresentation
bin11111110000101001…
…010101110010010101
310021000122012012122012
4133300221111302111
51024320121440203
623355531114005
72315040256562
oct376051256225
9107018165565
1034102140053
111350a850623
1267388a2905
1332a61c93c7
141917189869
15d48d27bd8
hex7f0a55c95

34102140053 has 4 divisors (see below), whose sum is σ = 34154848800. Its totient is φ = 34049431308.

The previous prime is 34102140047. The next prime is 34102140067. The reversal of 34102140053 is 35004120143.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 34102140053 - 214 = 34102123669 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34102140073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26353403 + ... + 26354696.

It is an arithmetic number, because the mean of its divisors is an integer number (8538712200).

Almost surely, 234102140053 is an apocalyptic number.

It is an amenable number.

34102140053 is a deficient number, since it is larger than the sum of its proper divisors (52708747).

34102140053 is an equidigital number, since it uses as much as digits as its factorization.

34102140053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52708746.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 34102140053 its reverse (35004120143), we get a palindrome (69106260196).

The spelling of 34102140053 in words is "thirty-four billion, one hundred two million, one hundred forty thousand, fifty-three".

Divisors: 1 647 52708099 34102140053