34102500433 has 4 divisors (see below), whose sum is σ = 34105754788. Its totient is φ = 34099246080.

The previous prime is 34102500431. The next prime is 34102500473. The reversal of 34102500433 is 33400520143.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14735046544 + 19367453889 = 121388^2 + 139167^2 .

It is a cyclic number.

It is not a de Polignac number, because 34102500433 - 2¹ = 34102500431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34102500398 and 34102500407.

It is not an unprimeable number, because it can be changed into a prime (34102500431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1611408 + ... + 1632433.

It is an arithmetic number, because the mean of its divisors is an integer number (8526438697).

Almost surely, 2^34102500433 is an apocalyptic number.

It is an amenable number.

34102500433 is a deficient number, since it is larger than the sum of its proper divisors (3254355).

34102500433 is a wasteful number, since it uses less digits than its factorization.

34102500433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3254354.

The product of its (nonzero) digits is 4320, while the sum is 25.

The spelling of 34102500433 in words is "thirty-four billion, one hundred two million, five hundred thousand, four hundred thirty-three".