Base | Representation |
---|---|
bin | 10100010101010… |
… | …010010101010001 |
3 | 212202212220202021 |
4 | 110111102111101 |
5 | 1144311440213 |
6 | 53503251441 |
7 | 11311336606 |
oct | 2425222521 |
9 | 782786667 |
10 | 341124433 |
11 | 165612921 |
12 | 962a9b81 |
13 | 558993a0 |
14 | 3343a6ad |
15 | 1ee33d8d |
hex | 14552551 |
341124433 has 4 divisors (see below), whose sum is σ = 367364788. Its totient is φ = 314884080.
The previous prime is 341124391. The next prime is 341124437. The reversal of 341124433 is 334421143.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 44182609 + 296941824 = 6647^2 + 17232^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-341124433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 341124398 and 341124407.
It is not an unprimeable number, because it can be changed into a prime (341124437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13120158 + ... + 13120183.
It is an arithmetic number, because the mean of its divisors is an integer number (91841197).
Almost surely, 2341124433 is an apocalyptic number.
It is an amenable number.
341124433 is a deficient number, since it is larger than the sum of its proper divisors (26240355).
341124433 is a wasteful number, since it uses less digits than its factorization.
341124433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26240354.
The product of its digits is 3456, while the sum is 25.
The square root of 341124433 is about 18469.5542176848. The cubic root of 341124433 is about 698.7217714047.
Adding to 341124433 its reverse (334421143), we get a palindrome (675545576).
The spelling of 341124433 in words is "three hundred forty-one million, one hundred twenty-four thousand, four hundred thirty-three".
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