341131302542041 has 4 divisors (see below), whose sum is σ = 372143239136784. Its totient is φ = 310119365947300.

The previous prime is 341131302542033. The next prime is 341131302542057. The reversal of 341131302542041 is 140245203131143.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 341131302542041 - 2³ = 341131302542033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 341131302541988 and 341131302542006.

It is not an unprimeable number, because it can be changed into a prime (341131302542011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15505968297355 + ... + 15505968297376.

It is an arithmetic number, because the mean of its divisors is an integer number (93035809784196).

Almost surely, 2^{341131302542041} is an apocalyptic number.

It is an amenable number.

341131302542041 is a deficient number, since it is larger than the sum of its proper divisors (31011936594743).

341131302542041 is a wasteful number, since it uses less digits than its factorization.

341131302542041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31011936594742.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 341131302542041 its reverse (140245203131143), we get a palindrome (481376505673184).

The spelling of 341131302542041 in words is "three hundred forty-one trillion, one hundred thirty-one billion, three hundred two million, five hundred forty-two thousand, forty-one".