Base | Representation |
---|---|
bin | 1111100000110111000110… |
… | …01100110110011000010111 |
3 | 11110210022100010022112101112 |
4 | 13300123203030312120113 |
5 | 13432412334131430320 |
6 | 200315542555445235 |
7 | 10120454451023036 |
oct | 760334314663027 |
9 | 143708303275345 |
10 | 34114442061335 |
11 | a9629432001a9 |
12 | 39ab73575681b |
13 | 1605c93b0372c |
14 | 85d20d81671d |
15 | 3e25dcd22ec5 |
hex | 1f06e3336617 |
34114442061335 has 4 divisors (see below), whose sum is σ = 40937330473608. Its totient is φ = 27291553649064.
The previous prime is 34114442061289. The next prime is 34114442061377. The reversal of 34114442061335 is 53316024441143.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 34114442061335 - 240 = 33014930433559 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 34114442061292 and 34114442061301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3411444206129 + ... + 3411444206138.
It is an arithmetic number, because the mean of its divisors is an integer number (10234332618402).
Almost surely, 234114442061335 is an apocalyptic number.
34114442061335 is a deficient number, since it is larger than the sum of its proper divisors (6822888412273).
34114442061335 is an equidigital number, since it uses as much as digits as its factorization.
34114442061335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6822888412272.
The product of its (nonzero) digits is 414720, while the sum is 41.
The spelling of 34114442061335 in words is "thirty-four trillion, one hundred fourteen billion, four hundred forty-two million, sixty-one thousand, three hundred thirty-five".
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