Search a number
-
+
34121012143 = 523587111143
BaseRepresentation
bin11111110001110001…
…010101001110101111
310021001221201000021111
4133301301111032233
51024334434342033
623401443412451
72315356550341
oct376161251657
9107057630244
1034121012143
111351a470499
126743084127
1332aa0a631a
14191989d291
15d4a8047cd
hex7f1c553af

34121012143 has 8 divisors (see below), whose sum is σ = 34244800128. Its totient is φ = 33997448664.

The previous prime is 34121012111. The next prime is 34121012147.

34121012143 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 34121012143 - 25 = 34121012111 is a prime.

It is an alternating number because its digits alternate between odd and even.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34121012147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 251430 + ... + 362572.

It is an arithmetic number, because the mean of its divisors is an integer number (4280600016).

Almost surely, 234121012143 is an apocalyptic number.

34121012143 is a deficient number, since it is larger than the sum of its proper divisors (123787985).

34121012143 is a wasteful number, since it uses less digits than its factorization.

34121012143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112253.

The product of its (nonzero) digits is 576, while the sum is 22.

It can be divided in two parts, 341210 and 12143, that added together give a palindrome (353353).

The spelling of 34121012143 in words is "thirty-four billion, one hundred twenty-one million, twelve thousand, one hundred forty-three".

Divisors: 1 523 587 111143 307001 58127789 65240941 34121012143