34121111411203 has 4 divisors (see below), whose sum is σ = 36128235611880. Its totient is φ = 32113987210528.

The previous prime is 34121111411183. The next prime is 34121111411207. The reversal of 34121111411203 is 30211411112143.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 34121111411203 - 2¹³ = 34121111403011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (34121111411207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1003562100313 + ... + 1003562100346.

It is an arithmetic number, because the mean of its divisors is an integer number (9032058902970).

Almost surely, 2^{34121111411203} is an apocalyptic number.

34121111411203 is a deficient number, since it is larger than the sum of its proper divisors (2007124200677).

34121111411203 is a wasteful number, since it uses less digits than its factorization.

34121111411203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2007124200676.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 34121111411203 its reverse (30211411112143), we get a palindrome (64332522523346).

The spelling of 34121111411203 in words is "thirty-four trillion, one hundred twenty-one billion, one hundred eleven million, four hundred eleven thousand, two hundred three".