Search a number
-
+
3412113322133 = 9773492439429
BaseRepresentation
bin110001101001110001110…
…011010111000010010101
3110002012021001012011112102
4301221301303113002111
5421401002002302013
611131300410131445
7501342230461055
oct61516163270225
913065231164472
103412113322133
1110a60840202aa
12471359a20b85
131b99b792c279
14bb20bb75565
155db547e4d58
hex31a71cd7095

3412113322133 has 4 divisors (see below), whose sum is σ = 3415605762540. Its totient is φ = 3408620881728.

The previous prime is 3412113322067. The next prime is 3412113322139. The reversal of 3412113322133 is 3312233112143.

3412113322133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2059621079044 + 1352492243089 = 1435138^2 + 1162967^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3412113322133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3412113322096 and 3412113322105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3412113322139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1746218738 + ... + 1746220691.

It is an arithmetic number, because the mean of its divisors is an integer number (853901440635).

Almost surely, 23412113322133 is an apocalyptic number.

It is an amenable number.

3412113322133 is a deficient number, since it is larger than the sum of its proper divisors (3492440407).

3412113322133 is an equidigital number, since it uses as much as digits as its factorization.

3412113322133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3492440406.

The product of its digits is 7776, while the sum is 29.

Adding to 3412113322133 its reverse (3312233112143), we get a palindrome (6724346434276).

The spelling of 3412113322133 in words is "three trillion, four hundred twelve billion, one hundred thirteen million, three hundred twenty-two thousand, one hundred thirty-three".

Divisors: 1 977 3492439429 3412113322133