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3412141153 = 31247109199
BaseRepresentation
bin1100101101100001…
…0010010001100001
322210210112201201021
43023120102101201
523442002004103
61322330005441
7150361502251
oct31330222141
98723481637
103412141153
1114a1079173
127b2876881
13424bb7145
1424524b961
1514e854bbd
hexcb612461

3412141153 has 4 divisors (see below), whose sum is σ = 3412281600. Its totient is φ = 3412000708.

The previous prime is 3412141151. The next prime is 3412141157. The reversal of 3412141153 is 3511412143.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3412141153 - 21 = 3412141151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3412141151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23353 + ... + 85846.

It is an arithmetic number, because the mean of its divisors is an integer number (853070400).

Almost surely, 23412141153 is an apocalyptic number.

It is an amenable number.

3412141153 is a deficient number, since it is larger than the sum of its proper divisors (140447).

3412141153 is a wasteful number, since it uses less digits than its factorization.

3412141153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 140446.

The product of its digits is 1440, while the sum is 25.

The square root of 3412141153 is about 58413.5357002125. The cubic root of 3412141153 is about 1505.4823313212.

Adding to 3412141153 its reverse (3511412143), we get a palindrome (6923553296).

The spelling of 3412141153 in words is "three billion, four hundred twelve million, one hundred forty-one thousand, one hundred fifty-three".

Divisors: 1 31247 109199 3412141153