341230311341131 has 8 divisors (see below), whose sum is σ = 364383869731200. Its totient is φ = 318835886013120.

The previous prime is 341230311341119. The next prime is 341230311341201. The reversal of 341230311341131 is 131143113032143.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 341230311341131 - 2⁹ = 341230311340619 is a prime.

It is a super-2 number, since 2×341230311341131² (a number of 30 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 341230311341093 and 341230311341102.

It is not an unprimeable number, because it can be changed into a prime (341230311041131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 189783264586 + ... + 189783266383.

It is an arithmetic number, because the mean of its divisors is an integer number (45547983716400).

Almost surely, 2^{341230311341131} is an apocalyptic number.

341230311341131 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

341230311341131 is a deficient number, since it is larger than the sum of its proper divisors (23153558390069).

341230311341131 is a wasteful number, since it uses less digits than its factorization.

341230311341131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 379566531029.

The product of its (nonzero) digits is 7776, while the sum is 31.

Adding to 341230311341131 its reverse (131143113032143), we get a palindrome (472373424373274).

The spelling of 341230311341131 in words is "three hundred forty-one trillion, two hundred thirty billion, three hundred eleven million, three hundred forty-one thousand, one hundred thirty-one".