131143113032143 has 4 divisors (see below), whose sum is σ = 131372785735048. Its totient is φ = 130913440329240.

The previous prime is 131143113032119. The next prime is 131143113032171. The reversal of 131143113032143 is 341230311341131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131143113032143 - 2⁴⁵ = 95958740943311 is a prime.

It is a super-2 number, since 2×131143113032143² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131143119032143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114836350596 + ... + 114836351737.

It is an arithmetic number, because the mean of its divisors is an integer number (32843196433762).

Almost surely, 2^{131143113032143} is an apocalyptic number.

131143113032143 is a deficient number, since it is larger than the sum of its proper divisors (229672702905).

131143113032143 is an equidigital number, since it uses as much as digits as its factorization.

131143113032143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 229672702904.

The product of its (nonzero) digits is 7776, while the sum is 31.

Adding to 131143113032143 its reverse (341230311341131), we get a palindrome (472373424373274).

The spelling of 131143113032143 in words is "one hundred thirty-one trillion, one hundred forty-three billion, one hundred thirteen million, thirty-two thousand, one hundred forty-three".