Base | Representation |
---|---|
bin | 110001101001111110110… |
… | …110101111001000110111 |
3 | 110002012211022020221220201 |
4 | 301221332312233020313 |
5 | 421401424032423340 |
6 | 11131334231541331 |
7 | 501350530033621 |
oct | 61517666571067 |
9 | 13065738227821 |
10 | 3412332311095 |
11 | 10a61866a2a14 |
12 | 4713bb22a847 |
13 | 1b9a21104736 |
14 | bb22cc9bc11 |
15 | 5db68b5079a |
hex | 31a7edaf237 |
3412332311095 has 4 divisors (see below), whose sum is σ = 4094798773320. Its totient is φ = 2729865848872.
The previous prime is 3412332311081. The next prime is 3412332311099. The reversal of 3412332311095 is 5901132332143.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3412332311095 - 213 = 3412332302903 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3412332311099) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 341233231105 + ... + 341233231114.
It is an arithmetic number, because the mean of its divisors is an integer number (1023699693330).
Almost surely, 23412332311095 is an apocalyptic number.
3412332311095 is a deficient number, since it is larger than the sum of its proper divisors (682466462225).
3412332311095 is an equidigital number, since it uses as much as digits as its factorization.
3412332311095 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 682466462224.
The product of its (nonzero) digits is 58320, while the sum is 37.
The spelling of 3412332311095 in words is "three trillion, four hundred twelve billion, three hundred thirty-two million, three hundred eleven thousand, ninety-five".
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