341251404152143 has 8 divisors (see below), whose sum is σ = 343759929645440. Its totient is φ = 338743642650840.

The previous prime is 341251404152137. The next prime is 341251404152171.

341251404152143 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 341251404152143 - 2²⁹ = 341250867281231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 341251404152096 and 341251404152105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (341251404192143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 190101363 + ... + 191888068.

It is an arithmetic number, because the mean of its divisors is an integer number (42969991205680).

Almost surely, 2^{341251404152143} is an apocalyptic number.

341251404152143 is a deficient number, since it is larger than the sum of its proper divisors (2508525493297).

341251404152143 is a wasteful number, since it uses less digits than its factorization.

341251404152143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 381995997.

The product of its (nonzero) digits is 230400, while the sum is 40.

It can be divided in two parts, 34125140 and 4152143, that added together give a palindrome (38277283).

The spelling of 341251404152143 in words is "three hundred forty-one trillion, two hundred fifty-one billion, four hundred four million, one hundred fifty-two thousand, one hundred forty-three".