341253352143 has 12 divisors (see below), whose sum is σ = 537732555048. Its totient is φ = 206820213360.

The previous prime is 341253352109. The next prime is 341253352147.

341253352143 is a `hidden beast` number, since 3 + 4 + 125 + 3 + 3 + 521 + 4 + 3 = 666.

341253352143 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 341253352143 - 2¹⁰ = 341253351119 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 341253352098 and 341253352107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (341253352147) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1723501680 + ... + 1723501877.

It is an arithmetic number, because the mean of its divisors is an integer number (44811046254).

Almost surely, 2^341253352143 is an apocalyptic number.

341253352143 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

341253352143 is a deficient number, since it is larger than the sum of its proper divisors (196479202905).

341253352143 is a wasteful number, since it uses less digits than its factorization.

341253352143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3447003574 (or 3447003571 counting only the distinct ones).

The product of its digits is 129600, while the sum is 36.

It can be divided in two parts, 341253 and 352143, that added together give a palindrome (693396).

The spelling of 341253352143 in words is "three hundred forty-one billion, two hundred fifty-three million, three hundred fifty-two thousand, one hundred forty-three".