Base | Representation |
---|---|
bin | 11111110010000010… |
… | …010001001011100011 |
3 | 10021002021001120121202 |
4 | 133302002101023203 |
5 | 1024342103431003 |
6 | 23402122511415 |
7 | 2315442361466 |
oct | 376202211343 |
9 | 107067046552 |
10 | 34125452003 |
11 | 13521a231a5 |
12 | 674466556b |
13 | 32aac9c166 |
14 | 191a2d72dd |
15 | d4add0088 |
hex | 7f20912e3 |
34125452003 has 4 divisors (see below), whose sum is σ = 34125961200. Its totient is φ = 34124942808.
The previous prime is 34125451933. The next prime is 34125452071. The reversal of 34125452003 is 30025452143.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30025452143 = 23 ⋅1305454441.
It is a cyclic number.
It is not a de Polignac number, because 34125452003 - 28 = 34125451747 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34125452093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135500 + ... + 294297.
It is an arithmetic number, because the mean of its divisors is an integer number (8531490300).
Almost surely, 234125452003 is an apocalyptic number.
34125452003 is a deficient number, since it is larger than the sum of its proper divisors (509197).
34125452003 is an equidigital number, since it uses as much as digits as its factorization.
34125452003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 509196.
The product of its (nonzero) digits is 14400, while the sum is 29.
The spelling of 34125452003 in words is "thirty-four billion, one hundred twenty-five million, four hundred fifty-two thousand, three".
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