341310200031331 has 4 divisors (see below), whose sum is σ = 341710329223312. Its totient is φ = 340910070839352.

The previous prime is 341310200031293. The next prime is 341310200031349. The reversal of 341310200031331 is 133130002013143.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 341310200031331 - 2³⁵ = 341275840292963 is a prime.

It is a super-3 number, since 3×341310200031331³ (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 341310200031296 and 341310200031305.

It is not an unprimeable number, because it can be changed into a prime (341310200031371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200064594711 + ... + 200064596416.

It is an arithmetic number, because the mean of its divisors is an integer number (85427582305828).

Almost surely, 2^{341310200031331} is an apocalyptic number.

341310200031331 is a deficient number, since it is larger than the sum of its proper divisors (400129191981).

341310200031331 is an equidigital number, since it uses as much as digits as its factorization.

341310200031331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400129191980.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 341310200031331 its reverse (133130002013143), we get a palindrome (474440202044474).

The spelling of 341310200031331 in words is "three hundred forty-one trillion, three hundred ten billion, two hundred million, thirty-one thousand, three hundred thirty-one".