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341331432001 = 748761633143
BaseRepresentation
bin1001111011110001111…
…00000101001001000001
31012122000222022022120221
410331320330011021001
521043021321311001
6420445553103041
733442340205160
oct4757074051101
91178028268527
10341331432001
1112183777096a
125619b257a81
13262589a2b51
14127404933d7
158d2aee41a1
hex4f78f05241

341331432001 has 4 divisors (see below), whose sum is σ = 390093065152. Its totient is φ = 292569798852.

The previous prime is 341331431999. The next prime is 341331432023. The reversal of 341331432001 is 100234133143.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 341331432001 - 21 = 341331431999 is a prime.

It is not an unprimeable number, because it can be changed into a prime (341331432041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24380816565 + ... + 24380816578.

It is an arithmetic number, because the mean of its divisors is an integer number (97523266288).

Almost surely, 2341331432001 is an apocalyptic number.

It is an amenable number.

341331432001 is a deficient number, since it is larger than the sum of its proper divisors (48761633151).

341331432001 is an equidigital number, since it uses as much as digits as its factorization.

341331432001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48761633150.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 341331432001 its reverse (100234133143), we get a palindrome (441565565144).

The spelling of 341331432001 in words is "three hundred forty-one billion, three hundred thirty-one million, four hundred thirty-two thousand, one".

Divisors: 1 7 48761633143 341331432001