341341440451322 has 4 divisors (see below), whose sum is σ = 512012160676986. Its totient is φ = 170670720225660.

The previous prime is 341341440451321. The next prime is 341341440451343. The reversal of 341341440451322 is 223154044143143.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 235174155781321 + 106167284670001 = 15335389^2 + 10303751^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 341341440451322.

It is not an unprimeable number, because it can be changed into a prime (341341440451321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85335360112829 + ... + 85335360112832.

Almost surely, 2^{341341440451322} is an apocalyptic number.

341341440451322 is a deficient number, since it is larger than the sum of its proper divisors (170670720225664).

341341440451322 is a wasteful number, since it uses less digits than its factorization.

341341440451322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 170670720225663.

The product of its (nonzero) digits is 552960, while the sum is 41.

Adding to 341341440451322 its reverse (223154044143143), we get a palindrome (564495484594465).

The spelling of 341341440451322 in words is "three hundred forty-one trillion, three hundred forty-one billion, four hundred forty million, four hundred fifty-one thousand, three hundred twenty-two".