Base | Representation |
---|---|
bin | 110001101011000000011… |
… | …110000111001011001011 |
3 | 110002022200000200111000121 |
4 | 301223000132013023023 |
5 | 421411202341332303 |
6 | 11132035354444111 |
7 | 501420025032124 |
oct | 61530036071313 |
9 | 13068600614017 |
10 | 3413433152203 |
11 | 10a66a1032158 |
12 | 471667a33637 |
13 | 1b9b681bb1c9 |
14 | bb2d517904b |
15 | 5dbd06009bd |
hex | 31ac07872cb |
3413433152203 has 4 divisors (see below), whose sum is σ = 3413437418160. Its totient is φ = 3413428886248.
The previous prime is 3413433152201. The next prime is 3413433152221. The reversal of 3413433152203 is 3022513343143.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 3413433152203 - 21 = 3413433152201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3413433152201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 532375 + ... + 2666512.
It is an arithmetic number, because the mean of its divisors is an integer number (853359354540).
Almost surely, 23413433152203 is an apocalyptic number.
3413433152203 is a deficient number, since it is larger than the sum of its proper divisors (4265957).
3413433152203 is a wasteful number, since it uses less digits than its factorization.
3413433152203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4265956.
The product of its (nonzero) digits is 77760, while the sum is 34.
Adding to 3413433152203 its reverse (3022513343143), we get a palindrome (6435946495346).
The spelling of 3413433152203 in words is "three trillion, four hundred thirteen billion, four hundred thirty-three million, one hundred fifty-two thousand, two hundred three".
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