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3421105504053 = 31140368501351
BaseRepresentation
bin110001110010001001110…
…001110011111100110101
3110010001110201120100011020
4301302021301303330311
5422022411002112203
611135344551531353
7502111116660636
oct61621161637465
913101421510136
103421105504053
1110a9978961706
12473049389b59
131ba7bb8a2b83
14bb82211388d
155decde7a153
hex31c89c73f35

3421105504053 has 4 divisors (see below), whose sum is σ = 4561474005408. Its totient is φ = 2280737002700.

The previous prime is 3421105504027. The next prime is 3421105504057. The reversal of 3421105504053 is 3504055011243.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3421105504053 - 212 = 3421105499957 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3421105504057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 570184250673 + ... + 570184250678.

It is an arithmetic number, because the mean of its divisors is an integer number (1140368501352).

Almost surely, 23421105504053 is an apocalyptic number.

It is an amenable number.

3421105504053 is a deficient number, since it is larger than the sum of its proper divisors (1140368501355).

3421105504053 is a wasteful number, since it uses less digits than its factorization.

3421105504053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1140368501354.

The product of its (nonzero) digits is 36000, while the sum is 33.

The spelling of 3421105504053 in words is "three trillion, four hundred twenty-one billion, one hundred five million, five hundred four thousand, fifty-three".

Divisors: 1 3 1140368501351 3421105504053