Base | Representation |
---|---|
bin | 110001110010001001110… |
… | …001110011111100110101 |
3 | 110010001110201120100011020 |
4 | 301302021301303330311 |
5 | 422022411002112203 |
6 | 11135344551531353 |
7 | 502111116660636 |
oct | 61621161637465 |
9 | 13101421510136 |
10 | 3421105504053 |
11 | 10a9978961706 |
12 | 473049389b59 |
13 | 1ba7bb8a2b83 |
14 | bb82211388d |
15 | 5decde7a153 |
hex | 31c89c73f35 |
3421105504053 has 4 divisors (see below), whose sum is σ = 4561474005408. Its totient is φ = 2280737002700.
The previous prime is 3421105504027. The next prime is 3421105504057. The reversal of 3421105504053 is 3504055011243.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3421105504053 - 212 = 3421105499957 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3421105504057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 570184250673 + ... + 570184250678.
It is an arithmetic number, because the mean of its divisors is an integer number (1140368501352).
Almost surely, 23421105504053 is an apocalyptic number.
It is an amenable number.
3421105504053 is a deficient number, since it is larger than the sum of its proper divisors (1140368501355).
3421105504053 is a wasteful number, since it uses less digits than its factorization.
3421105504053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1140368501354.
The product of its (nonzero) digits is 36000, while the sum is 33.
The spelling of 3421105504053 in words is "three trillion, four hundred twenty-one billion, one hundred five million, five hundred four thousand, fifty-three".
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