Base | Representation |
---|---|
bin | 100110111001001100010111… |
… | …1011001001100101010111011 |
3 | 1122212022121011212112012102210 |
4 | 1031302120233121030222323 |
5 | 324320131110223131420 |
6 | 3211340045513030203 |
7 | 132026533155450060 |
oct | 11562305731145273 |
9 | 1585277155465383 |
10 | 342112120130235 |
11 | 9a009a31a72734 |
12 | 324537549b5363 |
13 | 118b805aa49170 |
14 | 606a45a390c67 |
15 | 29841c48429e0 |
hex | 137262f64cabb |
342112120130235 has 128 divisors (see below), whose sum is σ = 676681238016000. Its totient is φ = 143724546865152.
The previous prime is 342112120130219. The next prime is 342112120130279. The reversal of 342112120130235 is 532031021211243.
It is not a de Polignac number, because 342112120130235 - 24 = 342112120130219 is a prime.
It is a super-2 number, since 2×3421121201302352 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 8589503301 + ... + 8589543129.
It is an arithmetic number, because the mean of its divisors is an integer number (5286572172000).
Almost surely, 2342112120130235 is an apocalyptic number.
342112120130235 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
342112120130235 is a deficient number, since it is larger than the sum of its proper divisors (334569117885765).
342112120130235 is a wasteful number, since it uses less digits than its factorization.
342112120130235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67565.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 342112120130235 its reverse (532031021211243), we get a palindrome (874143141341478).
The spelling of 342112120130235 in words is "three hundred forty-two trillion, one hundred twelve billion, one hundred twenty million, one hundred thirty thousand, two hundred thirty-five".
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