Base | Representation |
---|---|
bin | 1001111101010001000… |
… | …10100010100110110010 |
3 | 1012201002122000222100201 |
4 | 10332220202202212302 |
5 | 21101140242341224 |
6 | 421101122105414 |
7 | 33501205246063 |
oct | 4765042424662 |
9 | 1181078028321 |
10 | 342130043314 |
11 | 122107543414 |
12 | 563827ab26a |
13 | 2635528a917 |
14 | 127b857a56a |
15 | 8d76194a44 |
hex | 4fa88a29b2 |
342130043314 has 4 divisors (see below), whose sum is σ = 513195064974. Its totient is φ = 171065021656.
The previous prime is 342130043267. The next prime is 342130043393. The reversal of 342130043314 is 413340031243.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 413340031243 = 223 ⋅1853542741.
It can be written as a sum of positive squares in only one way, i.e., 340606468225 + 1523575089 = 583615^2 + 39033^2 .
It is a super-2 number, since 2×3421300433142 (a number of 24 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85532510827 + ... + 85532510830.
Almost surely, 2342130043314 is an apocalyptic number.
342130043314 is a deficient number, since it is larger than the sum of its proper divisors (171065021660).
342130043314 is a wasteful number, since it uses less digits than its factorization.
342130043314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171065021659.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 342130043314 its reverse (413340031243), we get a palindrome (755470074557).
The spelling of 342130043314 in words is "three hundred forty-two billion, one hundred thirty million, forty-three thousand, three hundred fourteen".
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