Base | Representation |
---|---|
bin | 110001110011111101001… |
… | …101111000101101110101 |
3 | 110010020110200212220010211 |
4 | 301303331031320231311 |
5 | 422040342303242240 |
6 | 11140305054545421 |
7 | 502210114665316 |
oct | 61637515705565 |
9 | 13106420786124 |
10 | 3423042243445 |
11 | 10aa782120680 |
12 | 4734a9b08271 |
13 | 1baa39bcb106 |
14 | bb96742260d |
15 | 5e093ee3bea |
hex | 31cfd378b75 |
3423042243445 has 16 divisors (see below), whose sum is σ = 4744666041408. Its totient is φ = 2343044957440.
The previous prime is 3423042243433. The next prime is 3423042243527. The reversal of 3423042243445 is 5443422403243.
It is not a de Polignac number, because 3423042243445 - 213 = 3423042235253 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3423042243398 and 3423042243407.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1830502939 + ... + 1830504808.
It is an arithmetic number, because the mean of its divisors is an integer number (296541627588).
Almost surely, 23423042243445 is an apocalyptic number.
It is an amenable number.
3423042243445 is a deficient number, since it is larger than the sum of its proper divisors (1321623797963).
3423042243445 is a wasteful number, since it uses less digits than its factorization.
3423042243445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3661007780.
The product of its (nonzero) digits is 1105920, while the sum is 40.
Adding to 3423042243445 its reverse (5443422403243), we get a palindrome (8866464646688).
The spelling of 3423042243445 in words is "three trillion, four hundred twenty-three billion, forty-two million, two hundred forty-three thousand, four hundred forty-five".
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