Base | Representation |
---|---|
bin | 110001110100000011110… |
… | …010100010000010101101 |
3 | 110010020202101101011210201 |
4 | 301310003302202002231 |
5 | 422041104020410242 |
6 | 11140324034233501 |
7 | 502212624162424 |
oct | 61640362420255 |
9 | 13106671334721 |
10 | 3423152513197 |
11 | 10aa8293969aa |
12 | 47351aa25891 |
13 | 1baa569c91a1 |
14 | bb977d282bb |
15 | 5e09da264b7 |
hex | 31d03ca20ad |
3423152513197 has 8 divisors (see below), whose sum is σ = 3643490944512. Its totient is φ = 3204922584000.
The previous prime is 3423152513173. The next prime is 3423152513201. The reversal of 3423152513197 is 7913152513243.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3423152513197 - 231 = 3421005029549 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3423152513897) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 527122179 + ... + 527128672.
It is an arithmetic number, because the mean of its divisors is an integer number (455436368064).
Almost surely, 23423152513197 is an apocalyptic number.
It is an amenable number.
3423152513197 is a deficient number, since it is larger than the sum of its proper divisors (220338431315).
3423152513197 is a wasteful number, since it uses less digits than its factorization.
3423152513197 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1054251059.
The product of its digits is 680400, while the sum is 46.
Adding to 3423152513197 its sum of digits (46), we get a palindrome (3423152513243).
The spelling of 3423152513197 in words is "three trillion, four hundred twenty-three billion, one hundred fifty-two million, five hundred thirteen thousand, one hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •