Base | Representation |
---|---|
bin | 110001110101010110101… |
… | …110110011010001110111 |
3 | 110010101100100210021102012 |
4 | 301311112232303101313 |
5 | 422101431233403101 |
6 | 11141114103434435 |
7 | 502262252043116 |
oct | 61652656632167 |
9 | 13111310707365 |
10 | 3424544044151 |
11 | 110038292078a |
12 | 473848a55a1b |
13 | 1bac190a0b99 |
14 | bba6aa73c7d |
15 | 5e130c96bbb |
hex | 31d56bb3477 |
3424544044151 has 16 divisors (see below), whose sum is σ = 3669972945408. Its totient is φ = 3184008700800.
The previous prime is 3424544044147. The next prime is 3424544044171. The reversal of 3424544044151 is 1514404454243.
It is a cyclic number.
It is not a de Polignac number, because 3424544044151 - 22 = 3424544044147 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3424544044099 and 3424544044108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3424544044121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18492146 + ... + 18676416.
It is an arithmetic number, because the mean of its divisors is an integer number (229373309088).
Almost surely, 23424544044151 is an apocalyptic number.
3424544044151 is a deficient number, since it is larger than the sum of its proper divisors (245428901257).
3424544044151 is a wasteful number, since it uses less digits than its factorization.
3424544044151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 197542.
The product of its (nonzero) digits is 614400, while the sum is 41.
Adding to 3424544044151 its reverse (1514404454243), we get a palindrome (4938948498394).
The spelling of 3424544044151 in words is "three trillion, four hundred twenty-four billion, five hundred forty-four million, forty-four thousand, one hundred fifty-one".
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