Base | Representation |
---|---|
bin | 1111100100101110011110… |
… | …11010011010110001111101 |
3 | 11111021000011000112010012212 |
4 | 13302113033122122301331 |
5 | 13442101334014411112 |
6 | 200500545445510205 |
7 | 10133165611261505 |
oct | 762271732326175 |
9 | 144230130463185 |
10 | 34247254060157 |
11 | aa041a71026a6 |
12 | 3a11420112365 |
13 | 161566b446a98 |
14 | 86580c54aa05 |
15 | 3e5cb2991522 |
hex | 1f25cf69ac7d |
34247254060157 has 4 divisors (see below), whose sum is σ = 34827715993440. Its totient is φ = 33666792126876.
The previous prime is 34247254060111. The next prime is 34247254060213. The reversal of 34247254060157 is 75106045274243.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 34247254060157 - 216 = 34247253994621 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34247254060057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 290230966553 + ... + 290230966670.
It is an arithmetic number, because the mean of its divisors is an integer number (8706928998360).
Almost surely, 234247254060157 is an apocalyptic number.
It is an amenable number.
34247254060157 is a deficient number, since it is larger than the sum of its proper divisors (580461933283).
34247254060157 is an equidigital number, since it uses as much as digits as its factorization.
34247254060157 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 580461933282.
The product of its (nonzero) digits is 5644800, while the sum is 50.
The spelling of 34247254060157 in words is "thirty-four trillion, two hundred forty-seven billion, two hundred fifty-four million, sixty thousand, one hundred fifty-seven".
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