3425141131 has 4 divisors (see below), whose sum is σ = 3425263000. Its totient is φ = 3425019264.

The previous prime is 3425141129. The next prime is 3425141141. The reversal of 3425141131 is 1311415243.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1311415243 = 59 ⋅22227377.

It is a cyclic number.

It is not a de Polignac number, because 3425141131 - 2¹ = 3425141129 is a prime.

It is a super-2 number, since 2×3425141131² = 23463183534535918322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3425141096 and 3425141105.

It is not an unprimeable number, because it can be changed into a prime (3425141141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5020 + ... + 82918.

It is an arithmetic number, because the mean of its divisors is an integer number (856315750).

Almost surely, 2^3425141131 is an apocalyptic number.

3425141131 is a deficient number, since it is larger than the sum of its proper divisors (121869).

3425141131 is an equidigital number, since it uses as much as digits as its factorization.

3425141131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121868.

The product of its digits is 1440, while the sum is 25.

The square root of 3425141131 is about 58524.7053046831. The cubic root of 3425141131 is about 1507.3918297709.

Adding to 3425141131 its reverse (1311415243), we get a palindrome (4736556374).

The spelling of 3425141131 in words is "three billion, four hundred twenty-five million, one hundred forty-one thousand, one hundred thirty-one".