Base | Representation |
---|---|
bin | 110001110111010001100… |
… | …000111111100101100001 |
3 | 110010120122220222222221021 |
4 | 301313101200333211201 |
5 | 422120141112201423 |
6 | 11142054332125441 |
7 | 502364304420556 |
oct | 61672140774541 |
9 | 13116586888837 |
10 | 3426604022113 |
11 | 110123a703708 |
12 | 474122906881 |
13 | 1bb186ab815c |
14 | bbbc44a2a2d |
15 | 5e201a5595d |
hex | 31dd183f961 |
3426604022113 has 4 divisors (see below), whose sum is σ = 3426608792880. Its totient is φ = 3426599251348.
The previous prime is 3426604022069. The next prime is 3426604022159. The reversal of 3426604022113 is 3112204066243.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3426604022113 - 229 = 3426067151201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3426604022713) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1064023 + ... + 2825836.
It is an arithmetic number, because the mean of its divisors is an integer number (856652198220).
Almost surely, 23426604022113 is an apocalyptic number.
It is an amenable number.
3426604022113 is a deficient number, since it is larger than the sum of its proper divisors (4770767).
3426604022113 is an equidigital number, since it uses as much as digits as its factorization.
3426604022113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4770766.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 3426604022113 its reverse (3112204066243), we get a palindrome (6538808088356).
The spelling of 3426604022113 in words is "three trillion, four hundred twenty-six billion, six hundred four million, twenty-two thousand, one hundred thirteen".
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