Base | Representation |
---|---|
bin | 110001111011000000011… |
… | …100100011101111110011 |
3 | 110010222000021212120102022 |
4 | 301323000130203233303 |
5 | 422201343312123011 |
6 | 11144000210142055 |
7 | 502565531041013 |
oct | 61730034435763 |
9 | 13128007776368 |
10 | 3430612614131 |
11 | 1102a0742617a |
12 | 474a6128192b |
13 | 1bb6754275b1 |
14 | bc084a11c43 |
15 | 5e3889268db |
hex | 31ec0723bf3 |
3430612614131 has 8 divisors (see below), whose sum is σ = 3444569622384. Its totient is φ = 3416668526880.
The previous prime is 3430612614101. The next prime is 3430612614161. The reversal of 3430612614131 is 1314162160343.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (3430612614101) and next prime (3430612614161).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3430612614131 - 26 = 3430612614067 is a prime.
It is a super-2 number, since 2×34306126141312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3430612614091 and 3430612614100.
It is not an unprimeable number, because it can be changed into a prime (3430612614101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2697980 + ... + 3760361.
It is an arithmetic number, because the mean of its divisors is an integer number (430571202798).
Almost surely, 23430612614131 is an apocalyptic number.
3430612614131 is a deficient number, since it is larger than the sum of its proper divisors (13957008253).
3430612614131 is a wasteful number, since it uses less digits than its factorization.
3430612614131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6460501.
The product of its (nonzero) digits is 31104, while the sum is 35.
Adding to 3430612614131 its reverse (1314162160343), we get a palindrome (4744774774474).
The spelling of 3430612614131 in words is "three trillion, four hundred thirty billion, six hundred twelve million, six hundred fourteen thousand, one hundred thirty-one".
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