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34314140021 = 74902020003
BaseRepresentation
bin11111111101010010…
…000011100101110101
310021120102002220220212
4133331102003211311
51030233404440041
623432543035205
72323223243360
oct377522034565
9107512086825
1034314140021
111360948a307
12679789bb05
13330b0c5685
1419373b30d7
15d5c7528eb
hex7fd483975

34314140021 has 4 divisors (see below), whose sum is σ = 39216160032. Its totient is φ = 29412120012.

The previous prime is 34314140017. The next prime is 34314140027. The reversal of 34314140021 is 12004141343.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 34314140021 - 22 = 34314140017 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34314140027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2451009995 + ... + 2451010008.

It is an arithmetic number, because the mean of its divisors is an integer number (9804040008).

Almost surely, 234314140021 is an apocalyptic number.

It is an amenable number.

34314140021 is a deficient number, since it is larger than the sum of its proper divisors (4902020011).

34314140021 is an equidigital number, since it uses as much as digits as its factorization.

34314140021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4902020010.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 34314140021 its reverse (12004141343), we get a palindrome (46318281364).

The spelling of 34314140021 in words is "thirty-four billion, three hundred fourteen million, one hundred forty thousand, twenty-one".

Divisors: 1 7 4902020003 34314140021