Base | Representation |
---|---|
bin | 110001111011110111110… |
… | …011101001010010110010 |
3 | 110011001102000120102222222 |
4 | 301323313303221102302 |
5 | 422210244100204132 |
6 | 11144232305401042 |
7 | 502630536513401 |
oct | 61736763512262 |
9 | 13131360512888 |
10 | 3431541413042 |
11 | 1103343738586 |
12 | 475080339182 |
13 | 1bb792995352 |
14 | bc132107638 |
15 | 5e3e0241412 |
hex | 31ef7ce94b2 |
3431541413042 has 4 divisors (see below), whose sum is σ = 5147312119566. Its totient is φ = 1715770706520.
The previous prime is 3431541413033. The next prime is 3431541413071. The reversal of 3431541413042 is 2403141451343.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 2472941808481 + 958599604561 = 1572559^2 + 979081^2 .
It is a junction number, because it is equal to n+sod(n) for n = 3431541412993 and 3431541413011.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 857885353259 + ... + 857885353262.
Almost surely, 23431541413042 is an apocalyptic number.
3431541413042 is a deficient number, since it is larger than the sum of its proper divisors (1715770706524).
3431541413042 is a wasteful number, since it uses less digits than its factorization.
3431541413042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1715770706523.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 3431541413042 its reverse (2403141451343), we get a palindrome (5834682864385).
The spelling of 3431541413042 in words is "three trillion, four hundred thirty-one billion, five hundred forty-one million, four hundred thirteen thousand, forty-two".
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