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3433133324042 = 212589136354489
BaseRepresentation
bin110001111101010110101…
…100010011011100001010
3110011012111222000220100122
4301331112230103130022
5422222024112332132
611145054253503242
7503015146523342
oct61752654233412
913135458026318
103433133324042
111103a90294904
124754454a1b22
131bb987728316
14bc2436d3d22
155e484d93912
hex31f56b1370a

3433133324042 has 8 divisors (see below), whose sum is σ = 5150109087300. Its totient is φ = 1716430294944.

The previous prime is 3433133324017. The next prime is 3433133324063. The reversal of 3433133324042 is 2404233313343.

It can be written as a sum of positive squares in 2 ways, for example, as 3281492397121 + 151640926921 = 1811489^2 + 389411^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 3433133323993 and 3433133324011.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68152067 + ... + 68202422.

Almost surely, 23433133324042 is an apocalyptic number.

3433133324042 is a deficient number, since it is larger than the sum of its proper divisors (1716975763258).

3433133324042 is a wasteful number, since it uses less digits than its factorization.

3433133324042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 136367080.

The product of its (nonzero) digits is 186624, while the sum is 35.

Adding to 3433133324042 its reverse (2404233313343), we get a palindrome (5837366637385).

The spelling of 3433133324042 in words is "three trillion, four hundred thirty-three billion, one hundred thirty-three million, three hundred twenty-four thousand, forty-two".

Divisors: 1 2 12589 25178 136354489 272708978 1716566662021 3433133324042