Base | Representation |
---|---|
bin | 110001111101010110101… |
… | …100010011011100001010 |
3 | 110011012111222000220100122 |
4 | 301331112230103130022 |
5 | 422222024112332132 |
6 | 11145054253503242 |
7 | 503015146523342 |
oct | 61752654233412 |
9 | 13135458026318 |
10 | 3433133324042 |
11 | 1103a90294904 |
12 | 4754454a1b22 |
13 | 1bb987728316 |
14 | bc2436d3d22 |
15 | 5e484d93912 |
hex | 31f56b1370a |
3433133324042 has 8 divisors (see below), whose sum is σ = 5150109087300. Its totient is φ = 1716430294944.
The previous prime is 3433133324017. The next prime is 3433133324063. The reversal of 3433133324042 is 2404233313343.
It can be written as a sum of positive squares in 2 ways, for example, as 3281492397121 + 151640926921 = 1811489^2 + 389411^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 3433133323993 and 3433133324011.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68152067 + ... + 68202422.
Almost surely, 23433133324042 is an apocalyptic number.
3433133324042 is a deficient number, since it is larger than the sum of its proper divisors (1716975763258).
3433133324042 is a wasteful number, since it uses less digits than its factorization.
3433133324042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 136367080.
The product of its (nonzero) digits is 186624, while the sum is 35.
Adding to 3433133324042 its reverse (2404233313343), we get a palindrome (5837366637385).
The spelling of 3433133324042 in words is "three trillion, four hundred thirty-three billion, one hundred thirty-three million, three hundred twenty-four thousand, forty-two".
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