Base | Representation |
---|---|
bin | 110001111110001010011… |
… | …110001010110111011111 |
3 | 110011021202111122221120211 |
4 | 301332022132022313133 |
5 | 422230314010043033 |
6 | 11145320405153251 |
7 | 503045525452012 |
oct | 61761236126737 |
9 | 13137674587524 |
10 | 3434002034143 |
11 | 110439669563a |
12 | 4756483bb827 |
13 | 1bba956b7875 |
14 | bc2c6c27379 |
15 | 5e4d628e2cd |
hex | 31f8a78addf |
3434002034143 has 4 divisors (see below), whose sum is σ = 3482368260048. Its totient is φ = 3385635808240.
The previous prime is 3434002034131. The next prime is 3434002034161. The reversal of 3434002034143 is 3414302004343.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3434002034143 - 217 = 3434001903071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3434002434143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24183112846 + ... + 24183112987.
It is an arithmetic number, because the mean of its divisors is an integer number (870592065012).
Almost surely, 23434002034143 is an apocalyptic number.
3434002034143 is a deficient number, since it is larger than the sum of its proper divisors (48366225905).
3434002034143 is an equidigital number, since it uses as much as digits as its factorization.
3434002034143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48366225904.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 3434002034143 its reverse (3414302004343), we get a palindrome (6848304038486).
The spelling of 3434002034143 in words is "three trillion, four hundred thirty-four billion, two million, thirty-four thousand, one hundred forty-three".
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