Base | Representation |
---|---|
bin | 110001111110001100111… |
… | …111110011001001110111 |
3 | 110011021212110101120120111 |
4 | 301332030333303021313 |
5 | 422230410331414333 |
6 | 11145324521243451 |
7 | 503046551551210 |
oct | 61761477631167 |
9 | 13137773346514 |
10 | 3434044404343 |
11 | 11044085a4a33 |
12 | 47565a633587 |
13 | 1bbaa14011a7 |
14 | bc2cc6d6407 |
15 | 5e4d9d5d4cd |
hex | 31f8cff3277 |
3434044404343 has 4 divisors (see below), whose sum is σ = 3924622176400. Its totient is φ = 2943466632288.
The previous prime is 3434044404293. The next prime is 3434044404379.
3434044404343 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 3434044404343 - 221 = 3434042307191 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3434044404296 and 3434044404305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3434044404643) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245288886018 + ... + 245288886031.
It is an arithmetic number, because the mean of its divisors is an integer number (981155544100).
Almost surely, 23434044404343 is an apocalyptic number.
3434044404343 is a deficient number, since it is larger than the sum of its proper divisors (490577772057).
3434044404343 is an equidigital number, since it uses as much as digits as its factorization.
3434044404343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 490577772056.
The product of its (nonzero) digits is 1327104, while the sum is 40.
The spelling of 3434044404343 in words is "three trillion, four hundred thirty-four billion, forty-four million, four hundred four thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •