Base | Representation |
---|---|
bin | 110001111110100010111… |
… | …111110010111010100001 |
3 | 110011022211011220200112021 |
4 | 301332202333302322201 |
5 | 422232134324031423 |
6 | 11145425304301441 |
7 | 503061653046046 |
oct | 61764277627241 |
9 | 13138734820467 |
10 | 3434413502113 |
11 | 1104587983610 |
12 | 475742171881 |
13 | 1bbb2ca12c39 |
14 | bc3257351cd |
15 | 5e50c46a95d |
hex | 31fa2ff2ea1 |
3434413502113 has 16 divisors (see below), whose sum is σ = 3876998227200. Its totient is φ = 3013621390080.
The previous prime is 3434413502081. The next prime is 3434413502123. The reversal of 3434413502113 is 3112053144343.
It is a cyclic number.
It is not a de Polignac number, because 3434413502113 - 25 = 3434413502081 is a prime.
It is a super-2 number, since 2×34344135021132 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3434413502123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 567993 + ... + 2681686.
It is an arithmetic number, because the mean of its divisors is an integer number (242312389200).
Almost surely, 23434413502113 is an apocalyptic number.
It is an amenable number.
3434413502113 is a deficient number, since it is larger than the sum of its proper divisors (442584725087).
3434413502113 is a wasteful number, since it uses less digits than its factorization.
3434413502113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3253032.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 3434413502113 its reverse (3112053144343), we get a palindrome (6546466646456).
The spelling of 3434413502113 in words is "three trillion, four hundred thirty-four billion, four hundred thirteen million, five hundred two thousand, one hundred thirteen".
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