Base | Representation |
---|---|
bin | 110001111110101001010… |
… | …111000001011110000111 |
3 | 110011100002121210021001120 |
4 | 301332221113001132013 |
5 | 422232344141114333 |
6 | 11145444040325023 |
7 | 503064420323043 |
oct | 61765127013607 |
9 | 13140077707046 |
10 | 3434520254343 |
11 | 11046321670a2 |
12 | 475771a73773 |
13 | 1bbb48b7bc39 |
14 | bc3359a3023 |
15 | 5e516a05db3 |
hex | 31fa95c1787 |
3434520254343 has 16 divisors (see below), whose sum is σ = 4705196307936. Its totient is φ = 2226816645120.
The previous prime is 3434520254329. The next prime is 3434520254387.
3434520254343 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 3434520254343 - 24 = 3434520254327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3434520254295 and 3434520254304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3434520254743) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6554038 + ... + 7058643.
It is an arithmetic number, because the mean of its divisors is an integer number (294074769246).
Almost surely, 23434520254343 is an apocalyptic number.
3434520254343 is a deficient number, since it is larger than the sum of its proper divisors (1270676053593).
3434520254343 is a wasteful number, since it uses less digits than its factorization.
3434520254343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13614994.
The product of its (nonzero) digits is 2073600, while the sum is 42.
It can be divided in two parts, 3434520 and 254343, that added together give a palindrome (3688863).
The spelling of 3434520254343 in words is "three trillion, four hundred thirty-four billion, five hundred twenty million, two hundred fifty-four thousand, three hundred forty-three".
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