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34368013543 = 259313254151
BaseRepresentation
bin100000000000011111…
…100100010011100111
310021201011110222111111
4200000133210103213
51030341202413133
623442145445451
72324446203133
oct400037442347
9107634428444
1034368013543
1113636936286
1267b1940887
133319308bb6
1419405d83c3
15d623451cd
hex8007e44e7

34368013543 has 4 divisors (see below), whose sum is σ = 34381270288. Its totient is φ = 34354756800.

The previous prime is 34368013489. The next prime is 34368013571. The reversal of 34368013543 is 34531086343.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 34368013543 - 233 = 25778078951 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34368013496 and 34368013505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34368013583) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6624483 + ... + 6629668.

It is an arithmetic number, because the mean of its divisors is an integer number (8595317572).

Almost surely, 234368013543 is an apocalyptic number.

34368013543 is a deficient number, since it is larger than the sum of its proper divisors (13256745).

34368013543 is a wasteful number, since it uses less digits than its factorization.

34368013543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13256744.

The product of its (nonzero) digits is 311040, while the sum is 40.

Adding to 34368013543 its reverse (34531086343), we get a palindrome (68899099886).

The spelling of 34368013543 in words is "thirty-four billion, three hundred sixty-eight million, thirteen thousand, five hundred forty-three".

Divisors: 1 2593 13254151 34368013543