Base | Representation |
---|---|
bin | 100000000010011101… |
… | …100100001101111001 |
3 | 10021210110122001211121 |
4 | 200002131210031321 |
5 | 1030423131341241 |
6 | 23445325425241 |
7 | 2325330020641 |
oct | 400235441571 |
9 | 107713561747 |
10 | 34401043321 |
11 | 13653546017 |
12 | 6800a0b221 |
13 | 3323101c48 |
14 | 1944b55521 |
15 | d651bbad1 |
hex | 802764379 |
34401043321 has 4 divisors (see below), whose sum is σ = 34480491892. Its totient is φ = 34321594752.
The previous prime is 34401043291. The next prime is 34401043349. The reversal of 34401043321 is 12334010443.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2823753321 + 31577290000 = 53139^2 + 177700^2 .
It is a cyclic number.
It is not a de Polignac number, because 34401043321 - 213 = 34401035129 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34401043021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39723636 + ... + 39724501.
It is an arithmetic number, because the mean of its divisors is an integer number (8620122973).
Almost surely, 234401043321 is an apocalyptic number.
It is an amenable number.
34401043321 is a deficient number, since it is larger than the sum of its proper divisors (79448571).
34401043321 is an equidigital number, since it uses as much as digits as its factorization.
34401043321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79448570.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 34401043321 its reverse (12334010443), we get a palindrome (46735053764).
The spelling of 34401043321 in words is "thirty-four billion, four hundred one million, forty-three thousand, three hundred twenty-one".
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