Base | Representation |
---|---|
bin | 100111000111000100111001… |
… | …1100111001101100101100001 |
3 | 1200010002000100100010121000011 |
4 | 1032032021303213031211201 |
5 | 330042411412403242423 |
6 | 3215400413440324521 |
7 | 132314433002045611 |
oct | 11616116347154541 |
9 | 1603060310117004 |
10 | 344020230134113 |
11 | 9a68518435a365 |
12 | 32701513013741 |
13 | 119c5c78a4ac60 |
14 | 60d494cd20a41 |
15 | 29b8b505aeb0d |
hex | 138e2739cd961 |
344020230134113 has 32 divisors (see below), whose sum is σ = 371448545126400. Its totient is φ = 316731138926400.
The previous prime is 344020230134101. The next prime is 344020230134149. The reversal of 344020230134113 is 311431032020443.
It is a cyclic number.
It is not a de Polignac number, because 344020230134113 - 241 = 341821206878561 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (344020230134153) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 39008979618 + ... + 39008988436.
It is an arithmetic number, because the mean of its divisors is an integer number (11607767035200).
Almost surely, 2344020230134113 is an apocalyptic number.
It is an amenable number.
344020230134113 is a deficient number, since it is larger than the sum of its proper divisors (27428314992287).
344020230134113 is a wasteful number, since it uses less digits than its factorization.
344020230134113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14293.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 344020230134113 its reverse (311431032020443), we get a palindrome (655451262154556).
The spelling of 344020230134113 in words is "three hundred forty-four trillion, twenty billion, two hundred thirty million, one hundred thirty-four thousand, one hundred thirteen".
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