Base | Representation |
---|---|
bin | 110010000011111100001… |
… | …000110101111001001100 |
3 | 110011212202201210010100100 |
4 | 302003330020311321030 |
5 | 422331014211410012 |
6 | 11152224035131100 |
7 | 503355314426265 |
oct | 62037410657114 |
9 | 13155681703310 |
10 | 3440204013132 |
11 | 1106a89530207 |
12 | 476899443a90 |
13 | 1bc543581613 |
14 | bc7147b196c |
15 | 5e74a9c28dc |
hex | 320fc235e4c |
3440204013132 has 72 divisors (see below), whose sum is σ = 8707425461280. Its totient is φ = 1145238151680.
The previous prime is 3440204013131. The next prime is 3440204013137. The reversal of 3440204013132 is 2313104020443.
3440204013132 is a `hidden beast` number, since 3 + 440 + 20 + 40 + 131 + 32 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 3440204013096 and 3440204013105.
It is not an unprimeable number, because it can be changed into a prime (3440204013131) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 131588782 + ... + 131614922.
It is an arithmetic number, because the mean of its divisors is an integer number (120936464740).
Almost surely, 23440204013132 is an apocalyptic number.
It is an amenable number.
3440204013132 is an abundant number, since it is smaller than the sum of its proper divisors (5267221448148).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3440204013132 is a wasteful number, since it uses less digits than its factorization.
3440204013132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30783 (or 30778 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 3440204013132 its reverse (2313104020443), we get a palindrome (5753308033575).
The spelling of 3440204013132 in words is "three trillion, four hundred forty billion, two hundred four million, thirteen thousand, one hundred thirty-two".
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