Base | Representation |
---|---|
bin | 1111101001010101000111… |
… | …00000110000001100110001 |
3 | 11111211010102122221010110021 |
4 | 13310222203200300030301 |
5 | 14002144310404010301 |
6 | 201101345325203441 |
7 | 10150465442610604 |
oct | 764524340601461 |
9 | 144733378833407 |
10 | 34405431313201 |
11 | aa65297035013 |
12 | 3a38005400581 |
13 | 1627558b8aac0 |
14 | 86d335d4633b |
15 | 3e9e6e3d08a1 |
hex | 1f4aa3830331 |
34405431313201 has 8 divisors (see below), whose sum is σ = 39002108371520. Its totient is φ = 30087340743312.
The previous prime is 34405431313189. The next prime is 34405431313219. The reversal of 34405431313201 is 10231313450443.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 34405431313201 - 221 = 34405429216049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34405431313271) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69646621845 + ... + 69646622338.
It is an arithmetic number, because the mean of its divisors is an integer number (4875263546440).
Almost surely, 234405431313201 is an apocalyptic number.
It is an amenable number.
34405431313201 is a deficient number, since it is larger than the sum of its proper divisors (4596677058319).
34405431313201 is a wasteful number, since it uses less digits than its factorization.
34405431313201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139293244215.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 34405431313201 its reverse (10231313450443), we get a palindrome (44636744763644).
The spelling of 34405431313201 in words is "thirty-four trillion, four hundred five billion, four hundred thirty-one million, three hundred thirteen thousand, two hundred one".
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