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34411312433 = 1719106536571
BaseRepresentation
bin100000000011000100…
…101111010100110001
310021211011221210102002
4200003010233110301
51030433243444213
623450333503345
72325513221021
oct400304572461
9107734853362
1034411312433
111365931a393
126804341b55
133325289144
141946269a81
15d66049658
hex80312f531

34411312433 has 8 divisors (see below), whose sum is σ = 38353165920. Its totient is φ = 30682532160.

The previous prime is 34411312381. The next prime is 34411312487. The reversal of 34411312433 is 33421311443.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 34411312433 - 216 = 34411246897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34411312396 and 34411312405.

It is not an unprimeable number, because it can be changed into a prime (34411372433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 53267963 + ... + 53268608.

It is an arithmetic number, because the mean of its divisors is an integer number (4794145740).

Almost surely, 234411312433 is an apocalyptic number.

It is an amenable number.

34411312433 is a deficient number, since it is larger than the sum of its proper divisors (3941853487).

34411312433 is a wasteful number, since it uses less digits than its factorization.

34411312433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106536607.

The product of its digits is 10368, while the sum is 29.

Adding to 34411312433 its reverse (33421311443), we get a palindrome (67832623876).

The spelling of 34411312433 in words is "thirty-four billion, four hundred eleven million, three hundred twelve thousand, four hundred thirty-three".

Divisors: 1 17 19 323 106536571 1811121707 2024194849 34411312433